Left Termination of the query pattern list_in_1(g) w.r.t. the given Prolog program could successfully be proven:



Prolog
  ↳ PrologToPiTRSProof

Clauses:

list([]).
list(.(X, Ts)) :- list(Ts).

Queries:

list(g).

We use the technique of [30].Transforming Prolog into the following Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:

list_in(.(X, Ts)) → U1(X, Ts, list_in(Ts))
list_in([]) → list_out([])
U1(X, Ts, list_out(Ts)) → list_out(.(X, Ts))

The argument filtering Pi contains the following mapping:
list_in(x1)  =  list_in(x1)
.(x1, x2)  =  .(x1, x2)
U1(x1, x2, x3)  =  U1(x3)
[]  =  []
list_out(x1)  =  list_out

Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog



↳ Prolog
  ↳ PrologToPiTRSProof
PiTRS
      ↳ DependencyPairsProof

Pi-finite rewrite system:
The TRS R consists of the following rules:

list_in(.(X, Ts)) → U1(X, Ts, list_in(Ts))
list_in([]) → list_out([])
U1(X, Ts, list_out(Ts)) → list_out(.(X, Ts))

The argument filtering Pi contains the following mapping:
list_in(x1)  =  list_in(x1)
.(x1, x2)  =  .(x1, x2)
U1(x1, x2, x3)  =  U1(x3)
[]  =  []
list_out(x1)  =  list_out


Using Dependency Pairs [1,30] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:

LIST_IN(.(X, Ts)) → U11(X, Ts, list_in(Ts))
LIST_IN(.(X, Ts)) → LIST_IN(Ts)

The TRS R consists of the following rules:

list_in(.(X, Ts)) → U1(X, Ts, list_in(Ts))
list_in([]) → list_out([])
U1(X, Ts, list_out(Ts)) → list_out(.(X, Ts))

The argument filtering Pi contains the following mapping:
list_in(x1)  =  list_in(x1)
.(x1, x2)  =  .(x1, x2)
U1(x1, x2, x3)  =  U1(x3)
[]  =  []
list_out(x1)  =  list_out
LIST_IN(x1)  =  LIST_IN(x1)
U11(x1, x2, x3)  =  U11(x3)

We have to consider all (P,R,Pi)-chains

↳ Prolog
  ↳ PrologToPiTRSProof
    ↳ PiTRS
      ↳ DependencyPairsProof
PiDP
          ↳ DependencyGraphProof

Pi DP problem:
The TRS P consists of the following rules:

LIST_IN(.(X, Ts)) → U11(X, Ts, list_in(Ts))
LIST_IN(.(X, Ts)) → LIST_IN(Ts)

The TRS R consists of the following rules:

list_in(.(X, Ts)) → U1(X, Ts, list_in(Ts))
list_in([]) → list_out([])
U1(X, Ts, list_out(Ts)) → list_out(.(X, Ts))

The argument filtering Pi contains the following mapping:
list_in(x1)  =  list_in(x1)
.(x1, x2)  =  .(x1, x2)
U1(x1, x2, x3)  =  U1(x3)
[]  =  []
list_out(x1)  =  list_out
LIST_IN(x1)  =  LIST_IN(x1)
U11(x1, x2, x3)  =  U11(x3)

We have to consider all (P,R,Pi)-chains
The approximation of the Dependency Graph [30] contains 1 SCC with 1 less node.

↳ Prolog
  ↳ PrologToPiTRSProof
    ↳ PiTRS
      ↳ DependencyPairsProof
        ↳ PiDP
          ↳ DependencyGraphProof
PiDP
              ↳ UsableRulesProof

Pi DP problem:
The TRS P consists of the following rules:

LIST_IN(.(X, Ts)) → LIST_IN(Ts)

The TRS R consists of the following rules:

list_in(.(X, Ts)) → U1(X, Ts, list_in(Ts))
list_in([]) → list_out([])
U1(X, Ts, list_out(Ts)) → list_out(.(X, Ts))

The argument filtering Pi contains the following mapping:
list_in(x1)  =  list_in(x1)
.(x1, x2)  =  .(x1, x2)
U1(x1, x2, x3)  =  U1(x3)
[]  =  []
list_out(x1)  =  list_out
LIST_IN(x1)  =  LIST_IN(x1)

We have to consider all (P,R,Pi)-chains
For (infinitary) constructor rewriting [30] we can delete all non-usable rules from R.

↳ Prolog
  ↳ PrologToPiTRSProof
    ↳ PiTRS
      ↳ DependencyPairsProof
        ↳ PiDP
          ↳ DependencyGraphProof
            ↳ PiDP
              ↳ UsableRulesProof
PiDP
                  ↳ PiDPToQDPProof

Pi DP problem:
The TRS P consists of the following rules:

LIST_IN(.(X, Ts)) → LIST_IN(Ts)

R is empty.
Pi is empty.
We have to consider all (P,R,Pi)-chains
Transforming (infinitary) constructor rewriting Pi-DP problem [30] into ordinary QDP problem [15] by application of Pi.

↳ Prolog
  ↳ PrologToPiTRSProof
    ↳ PiTRS
      ↳ DependencyPairsProof
        ↳ PiDP
          ↳ DependencyGraphProof
            ↳ PiDP
              ↳ UsableRulesProof
                ↳ PiDP
                  ↳ PiDPToQDPProof
QDP
                      ↳ QDPSizeChangeProof

Q DP problem:
The TRS P consists of the following rules:

LIST_IN(.(X, Ts)) → LIST_IN(Ts)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
By using the subterm criterion [20] together with the size-change analysis [32] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs: